Thread: little help please.

You're getting crazy numbers back for change because you're just working out how many quarters the change consists of, then how many dimes, etc. but you're not taking into account the fact that if you've already given back some of the change in quarters, you don't have to give the whole change back in dimes, etc.

Also, your code didn't compile as is, I had to remove the second "} /* end while loop */.

If you need two while loops, presumable one is so that the user can keep entering new input over and over, and the inner loop is so that the user can enter multiple items. You have inner loop done, so add the outer loop, with some condition:

Code:

int done = 0;
while (1)
{
    /* ask how many items, if they enter 0, break out of the outer while */
    while (numItems != 0)
    {
        /* the inner loop that asks the amount for each item and adds it to the total */
        numItems--;
    }
    /* the code that computes the change */
    /* the code that outputs the amount of change */
}

Of course, the assignment wants you to keep track of how many quarters/dimes, etc. the "bank" has, so you'll need an array, or separate counters to keep track of that, and decrease them as you use the coins appropriately. Presumably you'll need to check when they reach zero, and output that the bank has ran out of change?

ahhhh, im so totally lost its not funny, could you take my code and put statements in the spots i need to write certain code for, i undertsand what you are telling me im just lost as to where it all should go.

No, I've spelled it out for you enough. Use your brain. If you don't start using it now, you'll have no hope at all if you manage to move onto even vaguely advanced problems.

ok, i understand thanks for all your help. this is kind of advanced for me though, since i only started programming 2 weeks ago. but thanks again ill try and hammer it out for a while.

1st time posting...

touched up on ur programming, it was a rushed job...

doesnt really work (i.e. if u put 0 items on the 2nd or 3rd time round, it wont close.. read my notes at the end of the program. hope it helps u.

Code:

#include <stdio.h>

int main()
{
    int numItems;
    float price, amtPaid, total = 0, change;
    int quarters = 10, dimes = 10, nickels = 10, pennies = 10, count;

    printf("Please enter the number of grocery items: ");
    scanf("%d",&numItems); 

    
    while(numItems != 0) /* main while loop, makes sure your program works only if numItems not equal to 0.*/
    {
          
        count = 0;
        /*2nd loop, causes your program to ask repeatedly for the prices of your items, until numItems is met. */
        while(count<numItems)
       {
           printf("Please enter the price for your item>");
           scanf("%f", &price);
           total += price;
           count++;
       }
       
       
       printf("\n\nPlease enter the amount paid: ");
       scanf("%f",&amtPaid);
       
       change = amtPaid - total;
       
       printf("\nChange is %.2f\n", change);
       /* I don't understand your convertions */
       quarters = change / .25;
       dimes = change / .10;
       nickels = change / .05;
       pennies = change / .01;
       /*convertions... . */
       printf("The coins returned are: \n %d Quarters \n %d Dimes \n %d Nickels \n %d Pennies.\n", quarters, dimes, nickels, pennies);


       total = 0;
        
    } 
    return 0;

} /*end function main*/


//note on my program, you have to use a clr memory function, search around the forums. you have to clr up 
//the 'numItems' variable at the end of the loop good luck hahahah.
//and ther may be errors, i rushed thru it. but yes, u get the rough idea.

ahha, hope it posts right, i dont even know the tags ...

hey, thx for giving it a shot, i completed the program and got it turned in on time.

Impressive, very simple, easy to read

I wish I could help you man... i'm new to programming too, and loops can confuse me...