Array of strings

[blackswan]

Let's say I wanna read a strings from a file and store them into a string array.

char array [] [80];

[ZuK]

char array [] [80];

How many strings do you think that you allocate this way ?
BTW you forgot to ask a question.
Kurt

[blackswan]

Oh, yes I forgot. I was in a hurry... Okey, I know I can have strings like this:
char *array[]={"one", "two"....};

But I want to make an array of strings which wont be initialized at first. And then when Ill do the reading of the file, I want to add each line in the array.

so I first make ,let's say 80 strings array like this char *array[80], but how can I read lines from the file into that string.

fscanf(stream,``%s'', array[i]);

Would the above code work? I think I trieds this before ,but I think it didn't work...

[ZuK]

With the declaration

char *array[80];

you are only allocationg space for 80 pointers to strings and no space for the actual strings. You would have to do something like this:

char * array[80];
char buffer[200];
int cou = 0;
while ( cou < 80 && 1 == fscanf(stream,"%s", buffer) ) {
    array[cou]= malloc(strlen(buffer)+1);
    strcpy(array[cou], buffer);
    cou++;
}

don't forget to free the strings after using them
Kurt
edit: you are talking about reading the file line by line.
so check out fgets().

[cbastard]

Checkout the threads in 1 and 2 pages to find

char arr[];

why the statement is correct

[blackswan]

Thank's zook. That cleared my head