return problem

[peterx]

Hi!
.........................
if(...)
.....
else if(...)
.......
else
return a string.

after compiling and running the print out is=(AAAAAAAA8.00)

How can my program print out the String (AAAAAAAA) without 8.00

#include<stdio.h>
double my_program(double A, double B);
int main(){
  double C=20;
  double D=2;
  printf("%.2f\n", my_program(C,D));
  return 0;
}
double my_program(double A, double B){

  double new_v;
   if(A<=2.0)
  {
    return B;
  }
  else if(A >2 && A<15)
  {
    new_v=(2+(A*3));
    return new_v;
	}
  else
	  return printf("AAAAAAAA");

}

[quzah]

Your program doesn't return a string. It returns whatever value printf returns. You are calling the printf function, so it does its job, and then it returns a value, which you in turn also return.

Furthermore, you're using your function's return value in another printf statement, so that's always going to print whatever value you're giving it.

You need to reread the portion of whatever book you're using on returning variables from functions, and on calling functions, because you don't seem to be clear on how they work too well.


Quzah.

[sunnypalsingh]

This will work

#include<stdio.h>
#include<stdlib.h>
double my_program(double A, double B);
int main(){
  double C=20;
  double D=2;
  printf("%.2f\n", my_program(C,D));
  system("pause");
  return 0;
}
double my_program(double A, double B){

  double new_v;
   if(A<=2.0)
  {
    return B;
  }
  else if(A >2 && A<15)
  {
    new_v=(2+(A*3));
    return new_v;
	}
  else
	  {
           printf("AAAAAAAA");
           system("pause");
           exit(0);
      }
}

[peterx]

Hi!
Thank you for your help.
peter