Hello, is there a way in C to convert an int to a char* (a string). I have done the following:
sprintf(charptr,"%d",intvalue);
But, when I run the program, an "H" appends to numbers that are below 3 digits. Is there a clean way to convert an int to a char*? thanks in advance.
Sure, try using the function correctly. I don't see your sample code of how it "doesn't work". Post a full compilable sample code that "doesn't work" for us.
Quzah.
Hope is the first step on the road to disappointment.
sorry about that. out is the file descriptor and arr is the array ptr being passed in.
the only other changes i made to this code are in the write function:Code:void theoutput(int* arr,int out) { int x; char convert[50]; //buffer to hold int for(x = 0; x < ARRAY_SIZE; x++) { sprintf (convert, "%d", arr[x]); write(out, &convert, sizeof(&convert)); write(out, " : ", 3); } write(out,"\n",1); }
write(out, &convert, sizeof(&convert));
changed to
write(out, convert, sizeof(&convert));
the program compiles correctly with both versions, but still with the "H" being appended to numbers that are below 3 digits.
Why are you using the size of the address of the array as an argument? If you're trying to get the size of the string, use strlen. Also, an easy way to see if what you've got in the buffer is correct, just printf it real quick. But anyway, it's your incorrect usage of the third parameter of write that's your problem.Code:write(out, &convert, sizeof(&convert));
Quzah.
Hope is the first step on the road to disappointment.
also you don't want to pass the address over your char array to write() either, just pass the variable, it's already a pointer.
write(out, convert, sizeof(convert)); //or strlen(convert) instead of size if you don't want the null char and garbage after it.
