Thread: Assignment help

ok, I did that but it is still printing an extra row. I figured out that each identity matrix is supposed to have N-1 "1s" printed. I can make it so that it keeps track of the number of ones printed and when it reaches N-1 number of "1s" it will terminate out of the loop. how would I make it break out off this loop though? I know the break command, but putting it only makes it break out of the currecnt "else if (ones == N-1) statement when I tried it.

this is the code I tried but it just prints the exact same thing as the original:

Code:

#include <stdio.h>

#define N 15

int main()

{  float a[N][N];
   float *p;
   int zeros=0, ones=0;

a[0][0]=1;

for (p = &a[0][1]; p <= &a[N-1][N-1];  p++) {
  zeros++;
  if ( zeros == N+1 ) {
    *p = 1.0;
    zeros = 0;
    ones++;
      if (ones == N-1)
        break;
   }
   else {
    *p = 0.0;
  }
}

 for (p = &a[0][0]; p <= &a[N-1][N-1]; p++) {
   zeros++;
   if (zeros == N) {
     printf("\n");
     zeros = 0;
   }     
   else
    printf ("%.0f ", *p);
}

return 0;
}

Originally Posted by the_winky_files

how would I make it break out off this loop though? I know the break command, but putting it only makes it break out of the currecnt "else if (ones == N-1) statement when I tried it.

Code:

for (p = &a[0][1]; p <= &a[N-1][N-1];  p++) {
  zeros++;
  if ( zeros == N+1 ) {
    *p = 1.0;
    zeros = 0;
    ones++;
         }
   else {
    *p = 0.0;
  }
if (ones == N-1)
        break;
}

what you are trying to do with your second for loop???