Thread: Strings & Arrays

  1. #1

    Unhappy Strings & Arrays

    I need a program that 's able to place a character anywere in a string. This is what Iv got so far.

    #include <stdio.h>
    void strins(char string[], char character[], int position);
    char string[30];
    char str_ing;
    int i = 0;
    char character[1];
    int position;

    printf("Enter a string\n");

    str_ing = getchar();
    string[i] = str_ing;
    } while(str_ing != '\n');
    string[i-1] = '\0';
    printf("the letter and postion of correction\n");
    scanf("%s %d",character,&position);


    void strins(char string[], char character[], int position)
    int i;

    for (i=0, j=0;string[i] == character[position]; ++i, j++ )
    string[i] = character[position] + string[i];


    IT's in the function im getting confused, Thanks for any help.

  2. #2
    Registered User C_Coder's Avatar
    Join Date
    Oct 2001
    Try this, i changed a few things mainly i removed scanf and replaced it with fgets and sscanf, they're safer to use.
    I also used pointers as they are less messy than a load of square brackets, enjoy.
    #include <stdio.h>
    void strins(char *str_ptr, char ch, int pos);
    int main()
        char string[31], temp[5], ch;
        int pos;
        printf("\nEnter a string ");
        fgets(string, sizeof(string) - 1, stdin);
        printf("\nEnter letter and position of correction ");
        fgets(temp, sizeof(temp) - 1, stdin);
        sscanf(temp, "%c %d", &ch, &pos);
        strins(string, ch, pos);
        return 0;
    void strins(char *str_ptr, char ch, int pos)
        str_ptr += (pos - 1);
        *str_ptr = ch;
        str_ptr -= (pos - 1);  /* reset pointer */
    Last edited by C_Coder; 12-12-2001 at 03:31 PM.
    All spelling mistakes, syntatical errors and stupid comments are intentional.

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