Thread: Numbers In Words

Hi
I have coded this code to print numbers up to 32767 in words.

Well as a noob the job was tough for me.I want you all to read my code and tell me any flaw of it or a better logic to do it.

Code:

//	print numbers in word by 2d array

#include <stdio.h>
#include <conio.h>

int main(void)
{
char arr[10][6]={"","One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
char arr1[10][8]={"","Ten","Twenty","Thirty","Fourty","Fifty","Sixty","Seventy","Eighty","Ninety"};
char arr2[10][10]={"","Eleven","Tewelv","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};
int num;		//input by user
int k[5]={0,0,0,0,0};   //each digit is stored in this to make there order correct.Max 5 digit 32767.Intialized to zero because no garbage is shown.
int i;			//as usual for for loop
int flag=0;             //for not print zero b4 any digit
clrscr();
scanf("%d",&num);
printf("The number is %d\n",num);
if (num==0)
	printf("Zero");
else
{
for(i=4;num>0;i--)
{
    k[i]=num%10;
    num=num/10;
}
for(i=0;i<=4;i++)
  {
    if (k[i]>0 || flag==1)
     {
	if (i==4)
	    if(k[3]==1)
	    printf("%s ",arr2[k[i]]);
	    else
	    printf("%s ",arr[k[i]]);  //k[i] will give digit from which arr[] will print its equ. word
	else if (i==3)
	    if(k[3]==1 && k[4]>0)
	    {}
	    else
	    printf("%s ",arr1[k[i]]);
	else if (i==2 && k[i]>0)
	printf("%s Hundred ",arr[k[i]]);
	else if (i==1)
	{
	    if (k[0]==1)
	    {}
	    else
	    printf("%s ",arr[k[i]]);
	printf("Thousand ");
	}
	else if (i==0)
	{
	    if (k[0]==1 && k[1]>0)
	    printf("%s ",arr2[k[1]]);
	    else
	    printf("%s ",arr1[k[i]]);
	flag=1;
	}
     }
  }
}
getch();
return 0;
}

If some one feel uncomfortable for understanding it feel free to ask.