what im trying to do is go to another function, that the user enters..
after " printf ("your choice is %s", choice);"Code:#include <stdio.h> char choice[4]; int main() { printf ("enter a choice: ") ; scanf ("%s", choice); printf ("your choice is %s", choice); }
i want it to go to a function named after the variable choice...
for example if they enter math, i want it to go to the "math" function.
how would i do this , without a IF statement?
> how would i do this , without a IF statement?
With huge amounts of difficulty.
'C' isn't that kind of language.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Create a structure that contains a name and a function pointer, where all functions share the same prototype. Use an array of said structures, fixed at compile time. Use a loop + strcmp to check said array for selected name, and call the chosen function.
[edit]Of course, that usually would contain at least one if. I just noticed you didn't want any. Heh. That'll be more of the "huge amounts of difficulty". Or if not that, "exerciese in pointlessness".[/edit]
Now if you don't want them to all share the same prototype, that's where the "huge amounts of difficulty" come in...
Quzah.
Last edited by quzah; 08-20-2005 at 12:49 PM.
Hope is the first step on the road to disappointment.
My 2 cents.
Make a 2d array funcname storing the name(or the choices).Take a variable int a.
make a for loop.like for(i=0;strcmp(choice,funcname[i]);i++);
then you have value in int a corresponding to which function you want to call.Use a switch statement there.
what happened nobody responded.nobody pointed out an error.is everyone gawking at my stupidity
You mean the strcmp() == 0?
dwk
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you could also get around the strcmp. Since choice is only 4 char's long, you can use a switch statement.
I have those words backwards because I'm assuming you're working with a little endian machine. If you're big endian, write them as you would in proper English. If you don't know what endian means, you should find out.Code:switch( *((int *)choice) ) //this makes C think all 4 of those char's { //are individual bytes of an in case 'eno': //C will see this as an integer in the same fashion as well DoThisFunction(); break; case 'wto': DoThisOtherFunction(); break; }
from what you say i gather it's the same with Intel/Motorola
Two strings walk into a bar. The first one says, 'Bartender! Bartender! I want a drink!'. The second one says, 'Bartender! Bartender! I want a drink too! Blaaaaaaaaah eeeeeeeek yaaaaaaak oooooooh'. The first one says, 'Please excuse my friend. He isn't null term--'.
yup.strcmp returns int 0,if both strings are same.is'nt it? and in c it is considered as false so loop will breakOriginally Posted by dwks
Dont you think it will create some problem if the choices are of length 1 or 2?.May be i am wrong
Well if you're allowing switch/case, you can hide
> how would i do this , without a IF statement?
as
> switch( *((int *)choice)Code:switch ( (cond) != 0 ) { case 1: /* stuff for then*/ break; case 0: /* stuff for else*/ break; }
Not only do you have endian problems, you have alignment problems.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
If you're talking about having choices that are < 4 characters, then yes you have to be a bit tricky. If not, would you mind elaborating?
From the gcc manualOn some machines, accessing mis-aligned data will get you a 'bus error' exception.-Wcast-align
Warn whenever a pointer is cast such that the required alignment of the target is increased. For example, warn if a char * is cast to an int * on machines where integers can only be accessed at two- or four-byte boundaries.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
