Ok i got this code so far but iam sorta stuck right now.
Iam stuck on how to make it get the first letter of the nameCode:#include <stdio.h> void strip_newline( char *str, int size ) { int i; for ( i = 0; 1 < size; i++ ) { if ( str[i] == '\n' ) { str[i] = '\0'; } return; } } int main() { char name[50]; char letter[0];/*='k'*/ printf("Please enter your first name:"); scanf( "%s", letter ); }
Code:#include <stdio.h> int main(void) { char name[50]; printf("Please enter your first name: "); fflush(stdout); fgets(name, sizeof name, stdin); printf("The first letter is %c\n", name[0]); return 0; } /* my output Please enter your first name: Dave The first letter is D */
7. It is easier to write an incorrect program than understand a correct one.
40. There are two ways to write error-free programs; only the third one works.*
> for ( i = 0; 1 < size; i++ )
LOL - I can't believe you're still working with this broken code - you've posted the same code over and over, and never fixed it.
> return;
After peering through your broken indentation, it seems this function examines only one character and then exits.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Still works, it compiles and returns the repsonse i wanted it to return to me.Code:> for ( i = 0; 1 < size; i++ )
*ahem* i is not the same as 1.
7. It is easier to write an incorrect program than understand a correct one.
40. There are two ways to write error-free programs; only the third one works.*
I fixed it But next time ill look carefully at what i type
