Thread: getch problem

I have spen a lot of time trying to figure this out, but I can't get it through my head.

Code:

#include <stdio.h>
#include <stdlib.h>
#include <iostream.h>
#include <windows.h>
#include <wininet.h>
#include <time.h>
#include <conio.h>

//don't question the amount of includes please

int main()
{

	int c;
	FILE *fp;
	

   if ((fp = fopen("C:\\Documents and Settings\\Famliy\\Desktop\\loggerkey.txt", "wb")) == NULL)
   {
	   printf("Cannot open file for writing");
	   exit(EXIT_FAILURE);
   } 


  while (c = getch() != 'l')
   {
	  putchar(c);
	  fputc(c, fp);
   }
   fclose(fp);

   return 0;
} // main

Now, when I run this, everytime I press a key it is recorded as a "smiley face" character. And in the file, it is recorded as that vertical rectangle character (it kind of looks like this: []). Now I am wondering, why isn't getch recognizing the right character?

Code:

while (c = getch() != 'l')

Use parentheses to say what you mean.

Code:

while ((c = getch()) != 'l')

You had written this:

Code:

while (c = (getch() != 'l'))

[edit]

//don't question the amount of includes please

I won't question the amount, but I will question a C++ header for C code.

> //don't question the amount of includes please
Why not?
You've used C and C++ headers
You've used DOS and windows headers
No wonder there's confusion all around.

> loggerkey.txt"
I draw your attention to the forum rules about keyloggers and other malware.