Thread: string comparision : Urgent problem

Originally Posted by moonlord

there is a convention that says: if x is a pointer to something, or an array of that kind, then &a[0] == a

There's even a better one that says:

"If a function takes a given type, you can actually just pass it that given type without convoluting the hell out of it."

The function took a pointer to a character. So passing it one is correct. Passing some horribly ugly dereferenced / address of / dereferenced / address of mess doesn't make it any better. It just makes it harder to understand. Consider:

Code:

void foo( char * bar);

This function wants a pointer to a character. Thus, these are both correct:

Code:

char c;
char *p;

foo( &c ); /* the address of a character is a pointer to it */
foo( p ); /* a pointer to a character, since that's what it wants */

Oh, sure you could make it ugly as hell and still make it "correct":

Code:

char c;
char *p;

foo( &(*(&(*(&c)))) );
foo( &0[&*p] );

There's just no point in doing so.


Quzah.

Originally Posted by ILoveVectors

char sentence[30] = "whatever"; // orginal data
char *psentence = &sentence; // pointer to address of original data

Actually, the second line should just be:
char *psentence = sentence;

Remember that the name of an array by itself is actually a pointer to the first element of the array.

oops my mistake, i have to stop making post
when im half asleep.

yea and plus i most do c++ so i was prolly thinking this

Code:

#include <iostream>
#include <string>
using namespace std;

int main()
{
	string sentence2 = "whatever2";
	string *psentence2 = &sentence2;

	cout << sentence2 << endl;
	cout << *psentence2 << endl;
	cin.get();
	return 0;
}