Thread: string comparision : Urgent problem

  1. #16
    ATH0 quzah's Avatar
    Join Date
    Oct 2001
    Quote Originally Posted by moonlord
    there is a convention that says: if x is a pointer to something, or an array of that kind, then &a[0] == a
    There's even a better one that says:

    "If a function takes a given type, you can actually just pass it that given type without convoluting the hell out of it."

    The function took a pointer to a character. So passing it one is correct. Passing some horribly ugly dereferenced / address of / dereferenced / address of mess doesn't make it any better. It just makes it harder to understand. Consider:
    void foo( char * bar);
    This function wants a pointer to a character. Thus, these are both correct:
    char c;
    char *p;
    foo( &c ); /* the address of a character is a pointer to it */
    foo( p ); /* a pointer to a character, since that's what it wants */
    Oh, sure you could make it ugly as hell and still make it "correct":
    char c;
    char *p;
    foo( &(*(&(*(&c)))) );
    foo( &0[&*p] );
    There's just no point in doing so.

    Hope is the first step on the road to disappointment.

  2. #17
    Gawking at stupidity
    Join Date
    Jul 2004
    Oregon, USA
    Quote Originally Posted by ILoveVectors
    char sentence[30] = "whatever"; // orginal data
    char *psentence = &sentence; // pointer to address of original data
    Actually, the second line should just be:
    char *psentence = sentence;

    Remember that the name of an array by itself is actually a pointer to the first element of the array.
    If you understand what you're doing, you're not learning anything.

  3. #18
    Join Date
    Jun 2005
    oops my mistake, i have to stop making post
    when im half asleep.

    yea and plus i most do c++ so i was prolly thinking this

    #include <iostream>
    #include <string>
    using namespace std;
    int main()
    	string sentence2 = "whatever2";
    	string *psentence2 = &sentence2;
    	cout << sentence2 << endl;
    	cout << *psentence2 << endl;
    	return 0;
    Last edited by ILoveVectors; 08-08-2005 at 07:47 PM.

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