# Time to seconds program

• 06-13-2005
Sure
Time to seconds program
This is what i gotta do:

Create a C function called SecondsSinceMidnight() that has 3 parameters of type "long". The 3 parameters will be: "hours", "minutes" and "seconds". This function will use the 3 arguments passed to it to calculate and return (as a type "long" value) the number of seconds since the clock "struck midnight". The "hours" value passed to the function will be in military time (0 to 23). For example, if the input to the function (the value of the arguments passed to the function)is 15 hours, 5 minutes and 10 seconds, the function should return (15 * 60 * 60) + (5 * 60) + 10 = 54310 seconds.

Have your main() function input from the user two sets of time values. Have your main() program output the two sets of input times. Make use of the SecondsSinceMidnight() function to calculate the "seconds since midnight" for each of the two sets of input times. The main() function should then output the two results returned by the function (this means that you will need to invoke the SecondsSinceMidnight() function twice in your main() function). The main() function should then calculate the "difference in seconds" between the two values returned by the SecondsSinceMidnight() function and output the result. The "difference in seconds" should always be output as a positive number (you are allowed to use abs() -- the absolute value library function).

When you execute my .exe file, test it with the following 3 sets of data:

Data Set 1:

Enter the first hour value(0-23): 23
Enter the first minute value(0-59): 59
Enter the first second value(0-59): 59

Enter the second hour value(0-23): 0
Enter the second minute value(0-59): 0
Enter the second second value(0-59): 0

Data Set 2:

Enter the first hour value(0-23): 12
Enter the first minute value(0-59): 15
Enter the first second value(0-59): 30

Enter the second hour value(0-23): 12
Enter the second minute value(0-59): 15
Enter the second second value(0-59): 31

Data Set 3:

Enter the first hour value(0-23): 17
Enter the first minute value(0-59): 15
Enter the first second value(0-59): 10

Enter the second hour value(0-23): 5
Enter the second minute value(0-59): 0
Enter the second second value(0-59): 45

Code:

``` #include <stdio.h> long SecondsSincemidnight(long hours, long minutes, long seconds); int main()         {         long hours;         long minutes;         long seconds;         long hours2;         long minutes2;         long seconds2;         long variable1;         long variable2;         long sum=0;                 do{                 printf("\nEnter the first hour value(0-23): ");                 scanf("%ld", &hours);                 }while(hours>23);         do{                 printf("Enter the first minute value(0-59): ");                 scanf("%ld", &minutes);                 }while(minutes>59);         do{                 printf("Enter the first second value(0-59): ");                 scanf("%ld", &seconds);                 }while(seconds>59);                         do{                 printf("\nEnter the second hour value(0-23): ");                 scanf("%ld", &hours2);                 }while(hours2>23);         do{                 printf("Enter the second minute value(0-59): ");                 scanf("%ld", &minutes2);                 }while(minutes2>59);         do{                 printf("Enter the first second value(0-59): ");                 scanf("%ld", &seconds2);                 }while(seconds2>59);                 variable1 = SecondsSincemidnight(hours, minutes,  seconds);         printf("\nThe first input time converted into seconds is: %ld", variable1);                 variable2 = SecondsSincemidnight(hours2, minutes2,  seconds2);         printf("\nThe second input time converted into seconds is: %ld\n", variable2);         sum= variable1- variable2;                 if(sum<0)                 sum=-(sum);         printf("\nThe difference in seconds between the two input time is: %ld\n", sum);                         return  0;         } long SecondsSincemidnight(long a, long b, long c)         {         return a*3600+b*60+c;         }```

I cant seem to get it to say try again when u enter a negative #, also does this look alrite er can it be simplified

thx
• 06-13-2005
dwks
Quote:

Code:

```do{                 printf("\nEnter the first hour value(0-23): ");                 scanf("%ld", &hours);                 }while(hours>23);```

```do{     printf("\nEnter the first hour value(0-23): ");     scanf("%ld", &hours); } while(hours>23 && hours<0);```