sturct or union is given. how to swap it? exchange each data???
GCC said that It wasn't a structure or union in exchange(&sf1.k, &sf2.k), exchange(&sf1.s, &sf2.s) and exchange(&sf1.f &sf2.f);Code:#include <stdio.h> typedef struct { int k; int s; int f; }sfType; void exchange(int *x, int *y) { int t = *x; *x = *y; *y = t; } void exchangeSF(sfType *sf1, sfType *sf2) { exchange(&sf1.k, &sf2.k); exchange(&sf1.s, &sf2.s); exchange(&sf1.f, &sf2.f); } ........... int main() {.........}
Last edited by Mathsniper; 06-10-2005 at 08:13 AM.
Just use a temp variable of that type
Just like you'd do with anything else.Code:struct foo a, b, temp; temp = a; a = b; b = temp;
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
and here is one more example
s.s.harishCode:#include<stdio.h> struct student { char name[20]; int age; }; int main() { struct student s1={"Somename1",20}; struct student s2={"somename2",21},temp; temp=s1; s1=s2; s2=temp; printf("S1 - %s and his/her age -> %d\n",s1.name,s1.age); printf("S2 - %s and his/her age -> %d\n",s2.name,s2.age); getchar(); return 0; }
could you tell me how does gcc implement exchanging structure or union action?
If you have to identical struct datatypes but different varaibles use memcpy.
That what you mean by exchange?Code:typedef struct { int a; int b; } BLAH; ................ void BLAH_swap(BLAH *a, BLAH *b) { BLAH tmp={0,0}; memcpy(&tmp,a, sizeof(BLAH) ); memcpy(a,b,sizeof(BLAH) ); memcpy(b, &tmp, sizeof(BLAH) );
