with the declaration above is it ok to say the following? if not how can i do it??Code:letdef struct list_tag * list; struct list_tag { enum { ..... } kind; struct { int x; struct { int y; } nest1; } nest0; }
Code:list one; one = (list_tag *) malloc(sizeof(* one)); one.nest0.nest1.y = 2
> one = (list_tag *) malloc(sizeof(* one));
Don't cast malloc in C - see the FAQ.
> one.nest0.nest1.y = 2
one is a pointer, so you need the -> operator.
The rest is correct
one->nest0.nest1.y = 2
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
it should be
as one is a pointer of type listCode:one->nest0->nest1->y=2;
s.s.harish
No it shouldn't. nest0 is not a pointer, neither is nest1.Originally Posted by ssharish
Oh, and to the OP, you're missing a ; on your last braces.
Quzah.
Hope is the first step on the road to disappointment.
oops.. sorry, you are right quzah,
thax
