int a = 1, b = 2, c = 3;
a += b += c += 7
Interpreting what I read on page 64 in the same text, I derive the following:
c = c + 7, which now means that c = 10 = 3 + 7, followed by
b = b + c, which now means that b = 12 = 10 + 2, followed by
a = a + b, which now means that a = 13 = 12 + 1
Am I on target?
If not, would you steer me in the right direction?
Thx, Daniel
Last edited by AntonsonDJ; 05-08-2005 at 07:45 PM. Reason: clarification of my msg
Yes, you are. Of course it's probably easier to put that code in a compiler and run it, then post it on this forum and wait for an answer.Am I on target?
> Of course it's probably easier to put that code in a compiler and run it
True, but had the expression been one of those stupid i++ + ++i type things which seem to crop up from time to time, then they would have been wise to post the question.
Trying and compiling is also good
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
and here is a sample code of how do they work when u implement it
and my outputCode:#include<stdio.h> int main() { int a=10,b=20,c=30; int result; a+=b+=c+=10; printf("Result: %d\n",a); a=10,b=20,c=30; c = c + 10; b = b + c; a = a + b; printf("Result: %d",a); getchar(); return 0; }
s.s.harishCode:Result: 70 Result: 70
