Thread: Problem with char and char*

I have got a lot of errors from the line which has the 3 if statements in it.

Code:

C:\WINDOWS\Desktop\code.c(21): error #2168: Operands of == have illegal types 'char' and 'char *'.

C:\WINDOWS\Desktop\code.c(21): error #2157: Unrecognized statement.

C:\WINDOWS\Desktop\code.c(21): error #2001: Syntax error; found 'if' expecting ';'.
C:\WINDOWS\Desktop\code.c(21): error #2168: Operands of == have illegal types 'char' and 'char *'.

C:\WINDOWS\Desktop\code.c(21): error #2157: Unrecognized statement.

C:\WINDOWS\Desktop\code.c(21): error #2001: Syntax error; found 'if' expecting ';'.

C:\WINDOWS\Desktop\code.c(21): error #2168: Operands of == have illegal types 'char' and 'char *'.

C:\WINDOWS\Desktop\code.c(47): warning #2096: Missing return value.

C:\WINDOWS\Desktop\code.c(47): error #2001: Syntax error; found 'end of input' expecting '}'.

C:\WINDOWS\Desktop\code.c(21): error #2168: Operands of == have illegal types 'char' and 'char *'.

C:\WINDOWS\Desktop\code.c(21): error #2157: Unrecognized statement.

C:\WINDOWS\Desktop\code.c(21): error #2001: Syntax error; found 'if' expecting ';'.

C:\WINDOWS\Desktop\code.c(21): error #2168: Operands of == have illegal types 'char' and 'char *'.

C:\WINDOWS\Desktop\code.c(21): error #2157: Unrecognized statement.

C:\WINDOWS\Desktop\code.c(21): error #2001: Syntax error; found 'if' expecting ';'.

C:\WINDOWS\Desktop\code.c(21): error #2168: Operands of == have illegal types 'char' and 'char *'.

C:\WINDOWS\Desktop\code.c(47): warning #2096: Missing return value.

C:\WINDOWS\Desktop\code.c(47): error #2001: Syntax error; found 'end of input' expecting '}'.

How do I make the two types compatible with eachother so that the Operands of illegal types.... message goes away?

Code:

#include <stdio.h>

int main()
{
    FILE *f;
    char s[1000];

    f=fopen("file.txt","r");
    if (!f)
        return 1;
    while (fgets(s,1000,f)!=NULL)
 	{
	printf("Test");       
	printf("%s",s);
	if (s[1] == "N") && if (s[2] == "O") && if (s[3] == "P") {
		if (s[4] == 0) {
			printf("00 00 00 00 // NOP");
	} else {
		 printf("Syntax error. NOP should not have anything else after it");
}
}
    fclose(f);
    return 0;
}