the following thing works normal swapping: but
if change function call to
swap(a++,b++);
it dos'nt work why?
thanx!!Code:#include<stdio.h> #include<conio.h> void swap(int&, int&); int main() { int a = 10,b=20; swap(++a,++b); printf("\n%d\t%d\t",a, b); getch(); return 0; } void swap(int& x, int& y) { x+=2; y+=3; }
Think about it, when is post increment done compared to pre increment?
And just so you know, you code in C++ with C headers, references does not exist in C.
STL Util a small headers-only library with various utility functions. Mainly for fun but feedback is welcome.
Well I must say this "fall asleep on the keyboard" and compile it approach you seem to have to learning C (or is it C++ - do let us know which it is) isn't working out too well.
Whatever (or whoever) you're learning from is an idiot. There is no logic to any of your questions, just queries about how the latest bit of undefined behaviour is confusing you. You might think this will make you a programmer, but from where I'm sitting, you're heading in the wrong direction. Sure you might spoof your way through a few simple aptitude tests, but when it comes to writing real programs, you'll be out of luck.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
