Thread: simple array question

  1. #1

    simple array question

    hi, i'm trying to search for a character in a string array (see code below), but i'm stuck on how to display the character (if found in the string) at its correct position.

    for example, if letter='a' and orgWord="orange", it should display _ _ a _ _ _ .
    Thanks a lot.

    int MatchLetter(char* letter, char* orgWord) {
    char wordStr[50];
    int i;
    char *pdest;
    pdest = strchr( orgWord, letter );

    for (i=0; i<=strlen(orgWord); i++) {
    if (pdest!=NULL) { //letter found in string
    return 0;
    return 1;
    } //end if
    } //end else

    } //end function

  2. #2
    Code Goddess Prelude's Avatar
    Join Date
    Sep 2001
    This should work.
    The output is _ _ a _ _ _
    #include <stdio.h>
    #include <string.h>
    int main(){
        char array[] = "orange";
        int i = 0;
        while(i < strlen(array)){
            if(array[i] == 'a'){
    	    fputc(array[i], stdout); fputc(' ', stdout);
    	    fputc('_', stdout); fputc(' ', stdout);
        return 0;
    My best code is written with the delete key.

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