I'm having problems with using the "tolower".
I made a very small program to test:
Code:#include <stdio.h> #include <ctype.h> int main() { char ch; printf("Enter A Letter\n"); scanf("%c", ch); ch = tolower(ch); printf("%c", ch); return 0; }
This is what happens when I run the program:
The last line is the error. What am I doing wrong!?
Enter A Letter
G
Segmentation fault
Use
scanf("%c", &ch);
But because tolower and toupper functions take and return int, I suggest you to use
Code:int ch; ... ch = getchar(); ch = tolower(ch); ...
Last edited by Micko; 04-13-2005 at 12:22 PM.
Gotta love the "please fix this for me, but I'm not going to tell you which functions we're allowed to use" posts.
It's like teaching people to walk by first breaking their legs - muppet teachers! - Salem
Actually that's not it at all. The real problem is that your scanf call is wrong:
You forgot the address-of operator:Code:#include <stdio.h> #include <ctype.h> int main() { char ch; printf("Enter A Letter\n"); scanf("%c", ch); ch = tolower(ch); printf("%c", ch); return 0; }
Code:#include <stdio.h> #include <ctype.h> int main() { char ch; printf("Enter A Letter\n"); scanf("%c", &ch ); ch = tolower(ch); printf("%c", ch); return 0; }
Quzah.
Hope is the first step on the road to disappointment.
Really?Originally Posted by quzah
What about second line in my post?
Gotta love the "please fix this for me, but I'm not going to tell you which functions we're allowed to use" posts.
It's like teaching people to walk by first breaking their legs - muppet teachers! - Salem
I think he was talking about 98dodgeneondohc's post, not yoursWhat about second line in my post?
ok thanks for the help people!
Another thing... if I was to enter in a sentence, and I make an array for example: char sentence[50];
Upon running the program, I enter in the sentence seperated by a spacebar, it would only show the first word! How do I make it so it takes the whole sentence?
Last edited by 98dodgeneondohc; 04-14-2005 at 07:03 AM.
ok '&' is the one which give u the address, think of something like this
scanf the syantx is as followCode:int i; when u say _________ &i --> it gives you the address of 'i' i.e where the 'i' is located in the memory | | --------------- 1000 i so when u say &i --> it gives you the address of 'i ' in this case it is 1000
scanf function always requires address of the variable in order to place the value entered by the user. u are expected to specilfy '&' in front of the variable. in your caseCode:scanf("const char format", ... varibale);
the scanf is expecting the address of the variable ch to place u'r char eneted in the memoryCode:scanf("%c", ch);
>Upon running the program, I enter in the sentence seperated by a spacebar, it would only show the first word! How do I make it so it takes the whole sentence?
that is b'cose the scanf() fucntion reads the string up to the white space the rest is lost.
the better way of doing this is to use fgets function to read the string. and this syntax is as follow
[code]
fgets(char *, int, FILE *);
[code]
example:
hope this helpsCode:#include<stdio.h> int main() { char str[20]; fgets(str, sizeof str, stdin); // read the string printf("%s",str); // print the string on to the screen getchar(); } /* output: - hello world hello world */
s.s.harish
good explanation! thanks!
