Thread: Trim

Code:

#include <stdio.h>

char *trim( char *array )
{
    int i;
    
    for( ; *array == ' '; array++ );
    
    i = strlen( array );
    
    while( (--i > 0) && (array[i] == ' ') )
        array[i] = 0;
    
    return array;
}

int main()
{
    char a[] = "    hello world    ";
    
    trim( a );
    
    printf("%s", a);
    printf("!");
    
    printf("\n\n%s!", trim(a));
    
    return 0;
}

Do you guys see how my function doesn't change the string completely? It will really remove the blank spaces at the end, but not the ones in the front. How can I make my function modify the string passed to it? Thank you.

Code:

#include <stdio.h>

int Trim(char* buffer, char* s)
{
	int index = 0;
	int len = 0;
	for(; s[index] != '\0'; index++)
	{
		if (s[index] != ' ')
		{
			buffer[len] = s[index];
			len++;
		}
	}
	buffer[len] = 0;
	// returns the length of buffer:
	return len;
}

int main()
{
	char buff[256];
	char str[] = "|           Hello World   |";
	Trim(buff, str);
	printf("Normal string: %s\nSame string, but trimmed: %s\n", str, buff);
	system("pause"); // Not portable
	return 0;
}

Copy the char array to the buffer only if is not a blank space

@Micko: Thanks... I already know that
But since I'm more C++ than C... sometimes I mix those two

Is there a way to make my function change the array without the need of another variable?

Look at Salem's post, his solves your problem. Your function works, you're just not handling the return value correctly.