Thread: strlen()

Originally Posted by exoeight

yeah, that does work, but it wasn't in the specific way I was using it.

I had to do this... which still is a little flakey...

( key is a pointer pointing to a var that has a string in it passed through a function ).

Code:

char cKey[256];

  for( int i=0;i<strlen(key);i++ )
  cKey[ i ] = *(key+i);

then i could do:

Code:

maxCKey = strlen( cKey );

hah.



I guess if for some reason anyone else gets in to the situation I did, that's one way of doing it.


edit:
in the line: for( int i=0;i<strlen(key);i++ )

sizeof(key) doesn't make all of the key show
and strlen(key) loops way past actual key and makes funky symbols show.

lol. awesome.

First of all: you do realize that there is no such thing as a "string" data type in C, right?

All standard C library "string" functions (strlen(), strcpy(), etc., including printf("%s")) operate on a null-terminated sequence of chars.

1. The argument for strlen is (const *char), not (const char).

2. If you use the name of an array of char in an expression, it is treated as a pointer to char.

3. Your loop copies all of the chars up to but not including the terminating zero byte, so the result won't be useable with any standard C library string functions, including printf("%s"). So, your loop doesn't loop "way past the actual key", but trying to print the result with %s could go on forever.

4. If key points to a null-terminated sequence of chars and the the number of chars (including the terminating null) is not greater than the size of the char array cKey, then you can use this to copy the key into your array:

Code:

  strcpy(cKey, key)

Regards,

Dave