Wierd warning?

[St. Jimmy]

I get a warning when i declare a global integer variable extern?

extern int compflag

warning: compflag initialized and declared extern

but when initialize a char variable extern from some old code i found I don't have the same warning. This is causing a problem, I'm just curious as to why an integer does not need the extern while the char does?
Thanx a bunch for answering a really pointless question!

[bithub]

I'm guessing the warning is due to you doing something like:

extern int compflag = 10;

You should only initialize the variable where it is declared (not declared as extern). For example, what if you had the following in one file:

extern int compflag = 10;

and in another file you have:

int compflag = 11;

What does the value of compflag get initialized to?

[St. Jimmy]

i declare it

extern int compflag =0;

and there is no other declaration of it elsewhere.

[St. Jimmy]

I got rid of the initialization since the value that is stored gets changed at the start of each function that need it. It worked to I don't get that warning.
Thank you for your explaination.