help!

[DramaKing]

I have a problems with converting strings to number,
for example,
one thousand nine hundred eighty three -->> 1983

I have thought for a long long time, but couldn't think of how to do the coversion.

At the begining, I want to assign each number, i.e. one, two, three...ten, an array like a1[] = "one", a2[] = "two"......
that more than 10 arrays will be needed. The main problem is that I can't extract "one" in the string of words to compare. I really get stuck now, please help me. thx!!

[DramaKing]

I wrote something like that.....

#include "stdio.h"
#include "string.h"

#define MAXLINESIZE 1001
#define MAXWORDSIZE 50
#define MAXWORDNUMBER 20

void main()
{
char words[MAXWORDNUMBER][MAXWORDSIZE];
int i = 0, j = 0, k = 0, chr;

printf( "Enter Value : " );

/* This part is to split all words and assign each word to an array orderly */

for( k = 0; (k < MAXLINESIZE) && ((chr = getchar()) != EOF)
&& (chr != ' '); k++ ) {

if (chr != ' ') {
words[i][j] = (char) chr;
j++;
words[i][j] = null terminate; /* I cannot type null terminate */
}
else {
words[i][j] = null terminate; /* I cannot type null terminate */

i++;
j = 0;
}
}

/* At this moment 'i' is the upper value of array 'words'.
In other words, 'i+1' is the total no. of words you input. */

for (k = 0; k < i + 1; k++){
printf("%s ", words[k]);

/* wirte the conversion program */

}

return;
}



but I couldn't complie it... is there any errors? Pls point out for me....
thx a lot.......

[quzah]

If it doesn't compile, then yes, there are errors. If you pay attention to your compiler, it actually tells you what they are.

> void main()

This is right for your usage:

int main( void )

> if (chr != ' ') {

This will never execute because you've specified that if 'chr' is a space, then the loop will exit.

A null terminator is the value of zero. Commonly already defined as the word NULL.

Thus:

char *string = NULL;


Quzah.