Thread: Help with while loop

I am trying to write the beginning part of a program that has to read an array with 10 columns and the rows are not known but they are less than or equal to 150.

Code:

void main(void)
{
int num[3][10];

Well I guess then 3 won't be enough, will it? Oh, and go read the FAQ on why void main is wrong.

Quzah.

The 3 was a typo, thanks for pointing that out though, it should read:

Code:

#include <stdio.h>
void ReadArray(int[][10], int, int);

int main(void)
{
int num[150][10];
ReadArray(num, 150, 10);
}

Code:

while (num[r] != -1)
			{
		scanf("%d", &num[r][c]);
			}

Why are you doing this?

First off, even if it was right, you'd be looping until they entered "quit", in effect.
Second, you should be checking the row and the column, not just the row. Because just indexing the row gives you a pointer, which will not ever equal -1.
Third, even if this did work right, you still wouldn't be breaking out of your loop when -1 was entered. The for loops would still merrily chug along.
Fourth, why are you passing arbitrary numbers to control you second set of loops?


Quzah.

How about not sticking the "quit or not" value in first?

Code:

while( somevar != -1 )
{
    ...read into some var...
    if( somevar != -1 )
    {
        ...put this value into wherever you want it put...
    }
}

Quzah.