Thread: Program to reverse a number. small error with it..

hi! heres my program:

#include <stdio.h>
#include <math.h>
#define NEWLINE '\n'

int main(void){
int num;
int reverse(int n);

printf("Enter a positve integer: \n");
scanf("%i \n", &num);

printf("The reverse number is: %i \n", reverse(num));

return 0;
}

int reverse(int n)
{
int rev_num = 0, k = 0,i =2, mult = 1;
int rev_digit, digitcount;
int digits(int r);

digitcount = digits(n);

while((k <= digitcount) && (digitcount != 0))
{
rev_digit = n % 10;

k++;
mult = pow(10, (digitcount - k));

rev_num = rev_num + (rev_digit * mult);
n = n / 10;
}
return rev_num;
}

int digits(int r){
int count = 0;

while(r != 0)
{
r = r/10;
count++;
}

return count;
}


Output:
Enter a postive number:
8002033 /* for example */
2
/* this is where the problem occurs. after i enter 8002033, the program ask for another number, it doesnt matter what i enter, i just need to enter something */

The reverse is 3302008
/* this part seems correct */

So can anyone help me? i dont know why they need me to enter another number after 8002033!!

sorry heres the tagged code, i missed the top post

Code:

#include <stdio.h>
#include <math.h>
#define NEWLINE '\n'

int main(void){
	int num;
	int reverse(int n);

	printf("Enter a positive integer: \n");
	scanf("%i \n", &num); 

	printf("The reverse number is: %i \n", reverse(num));
	return 0;

}

int reverse(int n){
	int rev_num = 0, k = 0,i =2, mult = 1, rev_digit, digitcount;
                int digits(int r);
 
                digitcount = digits(n);

	while((k <= digitcount) && (digitcount != 0))
                {
                     rev_digit = n % 10;
	     k++;
	     mult = pow(10, (digitcount - k));
	     rev_num = rev_num + (rev_digit * mult);
                     n = n / 10;	    
	}
                return rev_num;            	
}

int digits(int r){
	int count = 0;

	while(r != 0)
                {
	      r  = r/10;
	      count++;
                }
	return count;
}

Code:

scanf("%i \n", &num);

Try

Code:

scanf("%i", &num);

YES!!! it worked!!
thank you!!!
you are brilliant!!!
thank you!!!
thank you!!!
thank you!!!

Assuming that you're using unsigned int number as input and ASCII,

Code:

void
print_reverse_number(const unsigned int number)
{
        const unsigned int      quotient = number / 10;
        const unsigned int      remainder = number % 10;


        putchar(remainder + '0');

        if (quotient != 0)
                print_reverse_number(quotient);
}

Bah quzah you forgot to check to see if its negative first

Always