How to get the current function name?

[tiranuch]

Is there anyway that I can get the current function name?
Like, if main() calls to function named "doit()".
When I'm in "doit()", I want to print out what the function name is.
It sounds silly because I can just printf("doit()\n");
But... is there any other ways??

Thank you.

[Salem]

Well that depends on your compiler...

[quzah]

As Salem stated. If you have a C99 compiler, you can use __func__ as described here.

Quzah.

[tiranuch]

It works!! Thank you.

I have one more question.
What about passing this parameter?
I want to pass this parameter to another function, which it will print who calls it.

I try to pass __func__ as a parameter for (char *), but it doesn't work.

[itsme86]

It works fine for me:

itsme@itsme:~/C$ cat func.c
#include <stdio.h>

void doit(const char *name)
{
  puts(name);
}

int main(void)
{
  doit(__func__);
  return 0;
}
itsme@itsme:~/C$ ./func
main
itsme@itsme:~/C$

[tiranuch]

Oh, it works now too.
I put doit(char *name) instead of doit(const char* name)
Now, I changed it and it works.

Thank you everybody