Thread: problem with for loop

Hi all, I have some code that I am trying to compile and every time I try I keep getting an error on the for loop.

I compiled this same code before without any problem with Dev C++ Compiler running both Win 98SE and XP. I originally got this code online as I wanted a random pasword generator. When I 1st got it I even made changes to suit my needs and it still compiled. I say that because I'm still a newbie to C. I will post the code below to see. Thanks in advance,

array

#include <stdio.h>
#include <stdlib.h>

char gen_letter(void)
{
char ch = (rand() % 26) + 'a';

return ch;
}

char gen_alphanum(void)
{
char vAlpha[] = "D9kc1ZayFj2mTds6Mx2Q8UiCp1J9uEoIw3Aq5GYL4gNr8WhBV 3PfH7KbX6l4SvL6Ot5n";
char ch = vAlpha[ rand() % 68 ];

return ch;
}

void gen_pass(char *sPassWord, int iSize)
{
if (iSize < 1)
{
sPassWord[0] = '\0';
return;
}

sPassWord[0] = gen_letter();

for ( i=1; i < iSize; i++)

sPassWord[i] = gen_alphanum();

sPassWord[iSize] = '\0';
}

int main(void)
{
char password[15];

srand((unsigned int) (GetTickCount() / 100) );

gen_pass(password, 14);
printf("\nPassword: ");
printf(" \n");
printf(" \n");


system("PAUSE");
return 0;
}

I saw that error but I wasn't quite sure exactly where to declare the variable.

So I declared it after this line of code:

void gen_pass(char *sPassWord, int iSize)

and I declared it like this:

char 'i';

and I got 4 errors

then I changed it to:

char i;

It compiled but all it did was print out the word Password:

Did I declare it in the right place or did I simply declare it wrong?

Thanks again to all that answered, array