One small problem!

[jfc]

Need to take in two variable ranges, 3 to 6 and 1 to 4. The program is supposed to calculate the cubed value of the ranges (432 & 100). I have written the functions and they work fine but I can't accumulate the totals! At the moment it is returninf the cubed values for the last digit of each range (54 & 36). Probably something really easy but I'm stuck! Here is the code:

#include<stdio.h>
#include<conio.h>

main()
{

int firsta,
lasta, /* first range */
firstb,
lastb, /*second range */
rangea,
rangeb;

int sum_of_cubes (int, int);

printf("Enter first range : ");
scanf("%d%d", &firsta, &lasta);
printf("Enter second range: ");
scanf("%d%d", &firstb, &lastb);

rangea = sum_of_cubes (firsta, lasta);
rangeb = sum_of_cubes (firstb, lastb);

printf("first range cubed %d\nsecond range cubed %d", rangea, rangeb);

getch();
}
int sum_of_cubes (int first, int last)
{
int number = first,
sum = 0,
parameter,
total;

int cube (int);

while (number <= last)
{
/* this is the bit I'm stuck on!!
parameter = cube(number);
sum = parameter;
number += 1;
*/
}

return sum;
}

cube (int item)
{
return item *3 *3;
}

[JFK]

Sorry, the JFC post below was meant to be me, if anyone is kind enough to reply can they do it through this one please? Thanks.

[Salem]

> return item *3 *3;
Cube is
item * item * item

[JFK]

Thanks Salem, I've been spending so long on this that I put a 3 instead times the item to the power of 3! Doh.

The program is still not giving me a combined total however, it's merely reporting the cube of the last digits in each range. Any ideas how to store them as a running total?

[JFK]

Cracked it.

[Salem]

int sum_of_cubes(int first, int last) { 
    int number = first, 
        sum = 0;
    while(number <= last) { 
        sum += cube( number ); 
        number ++; 
    } 
    return sum; 
}