newbie array help

[winnerpl]

Bah learning c here and I have trouble using arrays. very tricky for me.
How is this code can I get an array to make a table of rows and columns being the same number as inputted by the user:

#include <stdio.h>

int main(void)
{
	int input;
	int x,y;
	
	
	scanf("%d", &input);
					
	x=y=input;
	int table[x][y];
	
	return 0;	
}

Thanks guys in advance

[louis_mine]

to ask for the elements of an array you should always use a for()
like, for example, you want an user to give the number of rows and columns, so you should do something like this:

printf("number of rows");
scanf("%d", &row);
printf("number of columns");
scanf("%d", &col);

for(a=0;a<row;a++){
  for(b=0;b<col;b++)
	scanf("%d", table[a][b]);   //remember, [row][column], always is that way
	}

remember, you must always inizialize the variable as an array, giving a number of locations it should keep, example: arr[100][100]

[itsme86]

You need to use malloc() for that and then there's really no simple way to do it as a 2D array. You could try something like this:

itsme@itsme:~/C$ cat dynarray.c
#include <stdio.h>
#include <stdlib.h>

#define TABLE(y, x) (*((table) + (x) + (y) * (size)))

int main(void)
{
  char buf[10];
  int *table;
  int size;

  do
  {
    printf("Array size (1-9999)? ");
    fflush(stdout);
    fgets(buf, sizeof(buf), stdin);
    size = atoi(buf);
  } while(size < 1 || size > 9999);

  if(!(table = malloc(sizeof(int) * size * size)))
  {
    puts("Memory allocation error!");
    exit(EXIT_FAILURE);
  }

  TABLE(0, 0) = 3;
  printf("table[0][0] = %d\n", TABLE(0, 0));

  free(table);
  return EXIT_SUCCESS;
}
itsme@itsme:~/C$ ./dynarray
Array size (1-9999)? 10
table[0][0] = 3
itsme@itsme:~/C$