Thread: please help about switch

/*Program code for reference only*/
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
int main(void)
{
int play1,play2;
int rand1;
srand(time(NULL)); /*generate a random seed*/
rand1=rand()%3+1;/*generate a random number range from 1 to3*/


printf("\n\nPlayer 1 - Enter your choice?");
scanf("%d",&play1);

system("cls");

printf("\n\nPlayer 2 - Enter your choice?");
scanf("%d",&play2);

system("cls");

switch(play1)
{
case'1':
printf("\nPlayer 1 : Paper\n\n");
break;
case'2':
printf("\nPlayer 1 : Scissors\n\n");
break;
case'3':
printf("\nPlayer 1 : Stone\n\n");
break;
default:
printf("-");
}
switch(play2)
{
case'1':
printf("\nPlayer 2 : Paper\n\n");
break;
case'2':
printf("\nPlayer 2 : Scissors\n\n");
break;
case'3':
printf("\nPlayer 2 : Stone\n\n");
break;
default:
printf("-");
}


return 0;
}

why i can't show out what input of player 1 & 2
this is a part of my "c". please help

'1' is NOT the same as 1. '1' is a char, 1 is an integer.

Code:

int main(int argc, char *argv[]){
	printf("%d\n", sizeof('a'));
	return 0;
}

OUTPUT using MSVC++ 6:
1
OUTPUT using GCC in DJGPP:
4

The size of a constant char depends on the compiler implementation, but if its size is smaller that the variable to which is assigned, the leftover bytes are filled with 0's.
Me thinks....