Thread: How to compile a list of file?

I have a file name grp.c then i have a list of test file,
First i gcc -Wall -o grp grp.c

Then my question is that, what is the command that use to run a list of with grp.c.
I know that to run 1 file, is to use grp things to find < grp.c

Thanks in advance
diana

Here's a tip - paste your actual code, actual commands and actual output.

> I have a file name grp.c then i have a list of test file,
So for example,

you do this for one test file
grp test1.txt

you do this for many test files
grp test*.txt

you do this for a list of test files
ls test*.txt > list.txt
grp `cat list.txt`

Complete the implementation of grp program so that it implements the following features:

* ability to read input from a list of files specified on the command line (note that it must display the file name for any matching lines)
* the -v option to print lines that do not match the pattern
* the ^ anchor to indicate that the string should appear at the beginning of the line
* the $ anchor to indicate that the string should appear at the end of the line.



This is what i am suppose to do for my homework.
So how can i compile and test my program.

This is use to compile and run for one file:
compile the program via the command:

% gcc -Wall -o grp grp.c

You can then test it by running the executable on its own source code via the command:

% grp abc < grp.c
% grp line < grp.c

ability to read input from a list of files specified on the command line (note that it must display the file name for any matching lines)

You're not going to get that by redirecting stdin. What your instructor wants you to do is allow someone to type like:

grp searchstring file1 file2 file3

That way your search string is the first argument and every argument after that is a file to search for the string in. If you're still confused look at the man page for grep...it's the same sort of thing.

Ahh, get it, thanks