Thread: Need a little help.

I'm trying to make a program that tells you how much your worth in gold. Here is the code:

Code:

/* goldyou.c -- the worth of your weight in gold */

#include <stdio.h>

int main(void)
{
    float weight;         /*users weight*/
    float value;          /*user's gold equivalent*/

    printf("Are you worth your weight in gold?\n");
    printf("Let's find out.\n");
    printf("Please enter your weight in pounds: ");

/* get input from user */
    scanf("%f", &weight);
/* gold is worth $320 per ounce */
/* 14.5833 converts pounds to ounces */
    value = 320.0 * weight * 14.5833;
    printf("Your weight in gold is worth $%.2f.\n", value);
    printf("You are easily worth that!\n");
    printf("If gold prices drop, eat more to maintain your value.\n");
    getchar();
    return 0;
}

The program starts fine and lets me enter my weight. After I do and press enter the screen disappears. Any ideas?

-Fool

Try something like this:

#include <iostream.h>
#include <stdio.h>

main()
{
float weight, value;
cout<<"Are you worth your weight in gold?\n";
cout<<"Let's find out.\n";
cout<<"Please enter your weight in pounds: ";
cin>>weight;
value = 320 * weight * 14.5833;
cout<<"Your weight in gold is worth "<<value<<endl;
cout<<"You are easily worth that!\n";
cout<<"If gold prices drop, eat more to maintain your value.\n";
getchar();
return 0;
}

OK?

are you sure about those 320$???

-Ice- (IcyDeath)

Originally posted by Unregistered
Try something like this:

#include <iostream.h>
#include <stdio.h>

main()
{
float weight, value;
cout<<"Are you worth your weight in gold?\n";
cout<<"Let's find out.\n";
cout<<"Please enter your weight in pounds: ";
cin>>weight;
value = 320 * weight * 14.5833;
cout<<"Your weight in gold is worth "<<value<<endl;
cout<<"You are easily worth that!\n";
cout<<"If gold prices drop, eat more to maintain your value.\n";
getchar();
return 0;
}

OK?

are you sure about those 320$???

-Ice- (IcyDeath)

I need to only use C. The book I am studying from said $320. It's just for practice so it doesn't really matter.

-Fool

Ok, I added another printf and scanf to exit. Here's what I've got:

Code:

/* goldyou.c -- the worth of your weight in gold */

#include <stdio.h>

int main(void)
{
    float weight;         /*users weight*/
    float value;          /*user's gold equivalent*/
    float exit;           /*exit program*/

    printf("Are you worth your weight in gold?\n");
    printf("Let's find out.\n");
    printf("Please enter your weight in pounds: ");

/* get input from user */
    scanf("%f", &weight);
/* gold is worth $320 per ounce */
/* 14.5833 converts pounds to ounces */
    value = 320.0 * weight * 14.5833;
    printf("Your weight in gold is worth $%.2f.\n", value);
    printf("You are easily worth that!\n");
    printf("If gold prices drop, eat more to maintain your value.\n");
    printf("Please press enter to exit program: ");
    scanf("%f", &exit);
    return 0;
}

Now it will run the entire program but when you press enter to exit it will not exit. How can I do this?

-Fool

Where would I add in the int exit; ?

-Fool

If you're using most compilers use <conio.h> and getch() but if you're using Dev C++ you can use conio_mingw.h to use getch().

Code:

#include     <conio_mingw.h>
//Your includes


int main()
{

      //Your code

      getch();
      return 0;
}

Ok guys, I got it. Thanks for the help! Here's what it ended up looking like...

Code:

/* goldyou.c -- the worth of your weight in gold */

#include <stdio.h>

int main(void)
{
    float weight;         /*users weight*/
    float value;          /*user's gold equivalent*/
    float exit;           /*exit the program*/

    printf("Are you worth your weight in gold?\n");
    printf("Let's find out.\n");
    printf("Please enter your weight in pounds: ");

/* get input from user */
    scanf("%f", &weight);
/* gold is worth $320 per ounce */
/* 14.5833 converts pounds to ounces */
    value = 320.0 * weight * 14.5833;
    printf("Your weight in gold is worth $%.2f.\n", value);
    printf("You are easily worth that!\n");
    printf("If gold prices drop, eat more to maintain your value.\n");
    getch();
    return 0;
}

-Fool

In the conio.h that comes with Dev C++ it is, yeah. But I think most copies also have the Mingw implementation in which getch() behaves as it does on most other compilers.

Hi
as you know on the DOS/Windows platforms pressing the Enter key generates two symbols: <CR><LF>
so when you press the enter when filling the weight variable
the one <LF >left in the input stream so the getchar() eat it and exit immediately.

when you use the second 'scanf' it didn't exit becouse there is a simple validation used to enshure that there will be an nonempty string to be evaluated before the function return the value.

damyan