Thread: Need some help with my program please.

I really appreciate your advice.

Umm... Pablo615?

I executed what you typed, but it didn't work when I entered some values. But you did help me a little. This is what I have so far:

Code:

#include <stdio.h>

int main() {
  int i,j,k,num;
  printf("Enter a number: ");
  scanf("%d", &num);
  for(i=0; i<=num; i++) {
             for (j=0; j<=num; j++){
	         for (k=num; k>=i+j; k--){
		 printf("%d %d %d\n", i, j, k);
}
}
}

  return 0;
}

* I have some problems configuring this program the way I want it. Any advice on what I can do, is greatly appreciate it.*

What values were giving you problems? I've run it using lots of values (3, 8, 12, 102, 1212, etc) and I am getting the output I expect.

In the last loop, remember that the combined values of all 3 variables has to be EQUAL to num. Any other combination is wrong, so your "loop" should reflect that. All thats really needed is two loops, because one the first 2 values are decided, the third value is fixed.

Sorry, I posted bad code above, that was what I was playing with.

Use this.

Code:

int num, count, t1, t2, t3;
  printf("Enter a number: ");
  scanf("%d", &num);
  count = 0;
  for (t1 = 0; t1 <= num; t1++)
  {
    for (t2 = 0; t2 <= num; t2++)
    {
		/* This can replace the for loop.
		t3 = num - t1 - t2;
		if (t3 >= 0)
		{
			printf("%d %d %d\n", t1, t2, num - t1 - t2);
			count++;
		}
	}*/
	  for(t3 = num - t1 - t2; (t3 >= 0); t3--)
         {
            printf("%d %d %d\n", t1, t2, t3);
            count++;
            break;
      }
    }
  }
  printf ("Count = %d\n", count);
  return 0;
}

Don't forget to keep a counter for everytime you print. That will keep count for you.

Ok! The values I plugged in work now. Now I know how I can fix that third for loop. Thank you SO Much for your help!!!