Thread: comparing chars with pointer to char

  1. #1
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    Nov 2001
    Posts
    13

    comparing chars with pointer to char

    the code below is suppose to read from a file and to print out all alphanumeric characters(a-z,A-Z,0-0) spaces and newlines, throwing away the rest.
    Code:
    #include<stdio.h>
    #include<stdlib.h>
    #include<string.h>
    
    typedef char * STRNG;
    
    STRNG code[80];
    
    STRNG get_line(FILE * inf) {
        STRNG s = NULL;
        int count = 0;
        int tok;            // must be int - EOF is an int, not a char
    
        while ( (tok=getc(inf)) != EOF && tok != '\n' ) {
            if ( s == NULL ) s = malloc( 80 );
            s[count++] = tok;
        }
        if ( tok != EOF ) {
            if ( s == NULL ) s = malloc( 80 );  // possibly a newline on its own
            s[count++] = tok;                   // append the \n
            s[count] = '\0';
        }
        return s;
    }
    
    int main(int argc, char *argv[]) {
        char    *filename;
    	char    *loc;
        FILE    *stream;
        int     i,j, n = 0;            // Moved C++ declaration
        char alpha[64]={'q','w','e','r','t','y','u','i','o','p','a','s','d','f','g','h','j','k','l','m','n',
    	'b','v','c','x','z','Q','W','E','R','T','Y','U','I','O','P','L','K','J','H','G','F','D','S','A','Z',
    	'X','C','V','B','N','M','1','2','3','4','5','6','7','8','9','0',' ','\n'};
    
        filename =argv[1];
        stream=fopen(filename,"r");
        if(stream ==NULL)
        {
            printf("Enter a valid parameter.Program will exit.\n");
            exit(1);
        }
    
        while ( (code[n]=get_line(stream)) != NULL ) {
            n++;
        }
    
        printf( "%d lines found\n", n );
        for ( i = 0 ; i < n ; i++ )
    	    {
             for(j=0;j<64;j++)
    			 {
    			 loc=strstr(code[i],alpha[j]);
    			 if (loc!=NULL){
    				 printf("%s",alpha[j]);
    				           }
    			 }
    
             }
    
        return 0;  // 0 is success
    }
    anybody can suggest something better or help solve it?

  2. #2
    Registered User
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    Nov 2001
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    13
    i changed the code into this.now the characters that will be printed are passed through command line via argv, but i still do something wrong.help guys
    Code:
    #include<stdio.h>
    #include<stdlib.h>
    #include<string.h>
    
    typedef char * STRNG;
    
    STRNG code[80];
    
    STRNG get_line(FILE * inf) {
        STRNG s = NULL;
        int count = 0;
        int tok;            // must be int - EOF is an int, not a char
    
        while ( (tok=getc(inf)) != EOF && tok != '\n' ) {
            if ( s == NULL ) s = malloc( 80 );
            s[count++] = tok;
        }
        if ( tok != EOF ) {
            if ( s == NULL ) s = malloc( 80 );  // possibly a newline on its own
            s[count++] = tok;                   // append the \n
            s[count] = '\0';
        }
        return s;
    }
    
    int main(int argc, char *argv[]) {
        char    *filename;
    	char    *loc;
        FILE    *stream;
        int     i,j,k,m=0, n = 0;
        char   *alpha;
    	alpha=argv[1];
        filename =argv[2];
        stream=fopen(filename,"r");
    
        if(stream ==NULL)
        {
            printf("Enter a valid parameter.Program will exit.\n");
            exit(1);
        }
    
        while ( (code[n]=get_line(stream)) != NULL ) {
            n++;
        }
    while((k=getc(alpha))!='\0')
    	{
    		m++;
    	}
    	printf("%d\n",m);
        for ( i = 0 ; i < n ; i++ )
    	    {
             for(j=0;j<m;j++)
    			 {
    			 loc=strchr(code[i],alpha[j]);
    			 if (loc!=NULL){
    				 printf("%s",alpha[j]);
    				           }
    			 }
    
             }
    
        return 0;  // 0 is success
    }

  3. #3
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    I suggest you use isalpha() instead of searching through an array. You can also use a loopup table.
    // Gliptic

  4. #4
    Registered User
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    Nov 2001
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    13

    help

    somebody help guys

  5. #5
    ATH0 quzah's Avatar
    Join Date
    Oct 2001
    Posts
    14,826
    Don't be so impatient. We're not servents to respond to your every beck and call.

    You've already been told what to do. Use a loop and the function 'isalpha'.

    For example, given a buffer 'buf' that is a string of characters, to check them all, you can simply do:

    for( x = 0; buf[x]; x++ )
    if( isalpha( buf[x] ) ) printf("buf[%d] is %c\n", x, buf[x] );

    Quzah.
    Hope is the first step on the road to disappointment.

  6. #6
    and the hat of int overfl Salem's Avatar
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    > while((k=getc(alpha))!='\0')
    This doesn't even compile - or you're ignoring a serious warning. alpha is a char*, and getc expects a FILE*

    Besides, it looks like you should be doing
    m = strlen( alpha );

    > printf("%s",alpha[j]);
    To print a single character, its
    printf("%c",alpha[j]);

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