type conversions

**kocika73** · 10-06-2004

Hi guys, I've been studying type conversions and have some problems when running a simple display program. It prints out what I think might be some garbage and I do not get why. Can you take a look and tell me where I should look for an error? Thanks.

Code:

#include <stdio.h>


main()
{
char c = '\1';
short int s = 2;
int i = -3;
long int m = 5;
float f = 6.5;
double d = 7.5;

printf("%c %hd %d %ld %f %f\n", c, s, i, m, f, d);

printf("%d  %ld  %f  %ld %ld %d\n", c * i, s + m, f / c, d / s, f - d, (int) f); 
/*
(int, long int, float, double, double, int)
*/
return 0;
}

The results I am getting are:

2 -3 5 6.500000 7.500000
-3 7 6.500000 0 1074659328 0
It looks to me as if something does not get printed out...

**Dave_Sinkula** · 10-06-2004

I like Lint's helpful information.

Code:

#include <stdio.h>

int main(void)
{
   char c = '\1';
   short int s = 2;
   int i = -3;
   long int m = 5;
   float f = 6.5;
   double d = 7.5;

   printf("%c %hd %d %ld %f %f\n", c, s, i, m, f, d);

   printf("%d  %ld  %f  %ld %ld %d\n", c * i, s + m, f / c, d / s, f - d, (int) f);
/*
test.c 15: [559 Warning] Size of argument no. 5 inconsistent with format
test.c 15: [559 Warning] Size of argument no. 6 inconsistent with format
*/
   return 0;
}

Use %f for float or double values with printf.

**kocika73** · 10-06-2004

Oh, right, there is a difference between scanf and printf with specifications! Thanks! I really appreciate.

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