Thread: Copying an array of ints to a float, and vis versa

why do want to store the num in an int array you may as well store it in a long int and add subtract etc.

if however yr problem is to store and manipulate the number in an array
then you can
a) write a fn to add two arrays by adding two corresponding digits and if a carry is generated then carry it to the next number etc
once this is done multiplication shouldnt be too difficult

b) you can run a loop through the array
and multiply the place value with the digit and add the result to another variable that is of the type long int or float the manipulate it and
run another while loop dividing the result by succesive powers of 10 and putting the remainder back into the array at each stage

What they're getting at is this:

int array1[5] = { 1,2,3,4,5 };
int array2[5] = { 1,2,3,4,5 };
int array3[5] = { 0 };

You cannot just add these like you would:

array 3 = array1 + array 2 //not valid

If these were single integers:

int a1 = 12345, a2 = 12345 ,a3 =0;

a3 = a1+ a2; //valid

They're saying: if you want to us arrays as you describe above, you'll have to write your own math functions:

add( int array[], int size1, int array2[], int size2 )
{ go through each element, add them, carry the >10 repeat }

Quzah.