Thread: Concatenating strings (dynamic array using pointers)

Hey all,

Any ideas on how to concatenate strings that are refered to by an array of pointers to pointers? This is what I have at the moment:

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MAX_NO_STR 10
#define MAX_LGT_STR 99


main(int argc, char *argv[]) {
   char  **strings;
   int elements, i;

   strings = malloc( MAX_NO_STR * sizeof(char *) );
   if(strings == NULL) {
      fprintf(stderr, "out of memory\n");
      exit(1);
   }
   for(i = 0; i < MAX_NO_STR; i++) {
      strings[i] = malloc(MAX_LGT_STR * sizeof(int));
      if(strings[i] == NULL) {
         fprintf(stderr, "out of memory\n");
         exit(1);
       }
   }

   if(argc != 3) {
      strings[0]="Incorrect number of arguments for message ";
      strings[1]= "argv[2] will be used here";
      strings[2]=" generation";
      elements=3;
      catstrings(elements, strings);
      exit(1);
   } 

   for(i=0; i<MAX_NO_STR; i++) free(strings[i]);
   free(strings);

   exit(0);
}

catstrings(int elements, char **logmsg) {
   int i;

   for(i=1; i<elements; i++) {
      strcat(logmsg[0], logmsg[i]);
   }

}

The code compiles ok, but I get a segmentation fault each time I try to run it. I've tracked the error down to the line in the catstrings function that is supposed to perform the concatenation. Any ideas how I could achieve this or what the problem is?

Thanks in advance for your help.

Code:

strings[0]="Incorrect number of arguments for message ";

Strings[0] is pointing to allocated space and you are changing the pointer to a const string. Try strcpy instead:

Code:

strcpy(strings[0], "Incorrect number of arguments for message ");

Thanks Monster! That's done the trick!

The seperate strings were printing ok before concatenation so it didn't occur to me! That's what I get for looking at the same piece of code for too long!

Thanks again.

You're welcome.

b.t.w. you should also do this (strcpy) for strings[1] and strings[2], otherwise you will get problems releasing the allocated memory

Cheers. I figured as much and I've the whole thing working now for much larger systems as was the original plan.

Thanks.

Originally Posted by Salem

> strings[i] = malloc(MAX_LGT_STR * sizeof(int));
They're chars, not ints
strings[i] = malloc(MAX_LGT_STR * sizeof(char));

Or much easier to remember, and much easier to maintain
strings[i] = malloc(MAX_LGT_STR * sizeof *strings[i] );

Thanks for pointing that one out to me. I was adapting part of the code from a previous program and hadn't noticed that I didn't update that part.

Cheers.

Originally Posted by quzah

You're also going to have a nasty problem here, when you've concatenated all of these strings, and you realize that you've just run out of space on the first string you're tacking them all onto. You never check the size of any of your strings, and are assuming that all combine, they aren't going to run over 99 characters.

In your test program, this means that none of your "strings" can be more than 10 characters, because otherwise, your last concatenation is going to be a BadThingTM.

Quzah.

Thanks for the tip. I'm in the middle of writing something to do that as we speak