Could someone fix this for me?
Error: Constant out of range in comparison (if statement)
Code:static word force_reset_countdown = 99; if( abs( (int)force_reset_countdown-(int)( system_time.second * 1000 + system_time.millisecond ) ) > 120000 ) { ... }
did you try
?Code:static int force_reset_countdown = 99;
yes
same error
i'm sorry i'm dumb, i meant to ask if you tried static long int or long long int, and since you probably did, did you make sure you changed your type casts too? or remove them...
tried what you just said
same error :/
i'm guessing you're using #include <math.h> for abs(), but where are you getting system_time.second and system_time.millisecond from? are they your own structures or are you including something else?
either way it looks strange. int should work just fine for your "word" because the value is always 99. what exactly are you trying to do anyway? i'm really a noob (and i'm a noob to say that) but i guess i can't help
Last edited by linucksrox; 06-10-2004 at 10:47 PM.
What compiler are you using? What does this give you:
Quzah.Code:printf("sizeof( int ) is %d", sizeof( int ) );
Hope is the first step on the road to disappointment.
i'm working on an embedded environment
this is an intel chip
And? What is the size of int in your enviornment?
Quzah.
Hope is the first step on the road to disappointment.
gives me 2Code:sizeof( int )
2 bytes?
Yep. As such, you've got a limit of roughtly 32000. As such, 120000 is just a tad too big.
Quzah.
Hope is the first step on the road to disappointment.
should i declare them as double?
no, double is for floating-point, use long or maybe even long long if you want. you can do either long, or long int, whichever you prefer (same with long long or long long int) but long should be sufficient to handle 120000
If he only has 2 byte integers, I doubt his compiler or enviornment supports long long, and likely long is the same as int for size. Looks like he gets to rethink the problem.
Quzah.
Hope is the first step on the road to disappointment.
>and likely long is the same as int for size.
Why? An int must be able to hold a value in [-32767,32767], but a long must be able to hold a value in [-2147483647,2147483647].
7. It is easier to write an incorrect program than understand a correct one.
40. There are two ways to write error-free programs; only the third one works.*
