I know you can do:
char word[100];
int maxlen = sizeof(word);
//maxlen = 100;
But when I pass the string into a function, and then try this approach, it gives me the size of a char(4 bytes).
I am of course, trying to avoid passing the length of the string as a parameter.
I have tried:
char * string_func( char *in);
And also:
char * string_func( char in[]);
The results were identical.
Any ideas?
Code:#include <cmath> #include <complex> bool euler_flip(bool value) { return std::pow ( std::complex<float>(std::exp(1.0)), std::complex<float>(0, 1) * std::complex<float>(std::atan(1.0) *(1 << (value + 2))) ).real() < 0; }
> I am of course, trying to avoid passing the length of the string as a parameter.
Well you can't.
All arrays are passed as pointers to the first element, so all sizeof will be able to tell you is the size of that pointer.
Instead of:
int maxlen = sizeof(word);
Try:
int maxlen = strlen(word);
Since sizeof(word) will give the you size of the pointer to word (as it points to a char array). strlen(word) would be a better choice since it will return an int value that is the length of the word word is pointing to.
And don't forget #include<string.h>
Just a thought
DrakkenKorin
Get off my Intarweb!!!!
while calling, call as string_func(word);
and while declaring
use char *string_func( char word[100])
inside this function try strlen() to get the size of the string.
cheers,
I don't wait for the future; it comes soon enough.
strlen() only works on 'c' strings. If you wanted to check the length of any dynamically allocated pointer, just examine the block header.
