Thread: How to transfer value of a variable between functions

You need to use the return statement. Heres a simple example, otherwise check the FAQ.

Code:

int main()
{
     int i, j;
     i = 10;
     j = function1(i);
     return 0;
}

int function1(int i)
{
     int b;
     b = i 
     return b;
}

Now j is 10.

is this what you mean?

Code:

int function1(int i);

int main()
{
     
    int i = 10;
    int *ptr;

    ptr = &i;

    i = function1(i);

    return 0;
}

int function1(int i)
{
     i++;
     return i;
}

Originally Posted by pdkx7

Thanks ventolin, is there any way to do this with pointers?

There's really no need to do it with pointers if all you need is the value. If, on the other hand, you want changes made to the passed object to be reflected in the original object, you need to use pointers to simulate passing by reference:

Code:

#include <stdio.h>

void foo(int *p);

int
main(void)
{
  int i = 0;

  printf("In main: %d\n", i);
  foo(&i);
  printf("In main: %d\n", i);

  return 0;
}

void
foo(
  int *p
  )
{
  printf("In foo: %d\n", ++(*p));
}