stupid question???
how would i convert an int to a char ??
say weve got year, month, day as integers 2 digits long
ie 011114, held as a long int, or 3 separate ints
i want to save the date as a character string
this ought to be easy, but i'm struggling
am i as thick as a elephant sandwich ????
Steve
In the case of 3 separate ints.
One way is to use sprintf() in <stdio.h>.
For example:
>am i as thick as a elephant sandwich ????Code:int mon = 11; int day = 14; int year = 2001; char date[11]; sprintf(date,"%d/%d/%d",year,mon,day); //no leading zeros printf("%s\n",date); sprintf(date,"%#02d/%#02d/%#02d",year,mon,day); //leading zeros printf("%s\n",date);
hehe
Last edited by swoopy; 11-14-2001 at 05:24 PM.
thanx
thats a good way to do it !!!
Steve
I use long's
ie lDate=15112001;
I have macros
Combine this and Swoopies use of sprintf and you may have something.Code:#define GETDAY(lDate) (lDate / 1000000) #define GETMONTH(lDate) ((lDate / 10000) % 100) #define GETYEAR(lDate) (lDate % 10000)
(sprintf(sDate,"%d/%d/%d",GETDAY(lDate), ect)
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thats a neat solution, i like that thanx !!!
Steve
Actually, you cannot convert an int to a char. Even using itoa() or another function doesn't do this.
Please allow me to explain.
A char has 8-bits. It may contain an absolute value of 0-255.
An int (usually a short int) has 16-bits. It may contain an absolute value of 0-65535.
When you "convert" a 16-bit int to an 8-bit char, by default you are saying that your int will not be used for any number larger than 0-255 (or -127 to +127). If you try to use a number that is larger than these, when you do the conversion, the top 8-bits are stripped off.
In c, this is represented this way, and may converted to a macro as an exercise to the reader--
int a;
char b;
a = 5;
b = 0;
b = (char)(0x00FF & a);
------
where:
(char) coerces the resultant math to a form compatible with 'b'.
0x00FF is a mask to strip off the top 8-bits.
b == 5
-------
Let's say you have made 'a' larger than 255. What happens? Watch...
a = 27084 ; /* in hex that is: 0x680A */
b = 0;
b = (char)(0x00FF & a);
The stripping:
0x00FF &
0x680A
-------------
0x000A
b == 10 /* or 10 = 0x0A */
-----------------------------------------
enjoy.
Typo (for crying out loud I fat fingered the above)--
27084 = 0110 1001 1100 1100 in binary.
hex = 0x69CC
So the logic is:
0x00FF &
0x69CC
----------
0x00CC
b = 0xCC.
b = 204 decimal.
---
Sorry about that, I try to be accurate.
Theoretically, C does not recognize characters. Only ints that can be displayed as chars. For instance (don't quote me on the number -- I'm not sure if '40' is 'a'):
If 40 is == to 'a', then it will print out 'a', not an integer. To do a string, you can just loop through the whole string using this format.Code:int letter = 40; /* don't quote me on the char 'a' */ printf("The letter is %c\n", letter);
--Garfield
1978 Silver Anniversary Corvette
right, thanx guys, i'm much the wiser now !!!
learning all the time...............
Steve
/*this function works for #0 - 9 it will take a one digit # and convert it to ascii value*/
char int_to_ascii(int x)
{
char char_val ;
char_val = x | 0x0048 ; /* 48 is the ascii value of zero */
return char_val;
}
