okay heres my code
struct vector
{
char dataList[27];
};
int main(void)
{
struct vector listItem[10];
addData(listItem, data);
.
.
.
}
void addData(struct vector listItem[10], char data[27])
{
*listItem[index]->dataList = data;//why does this code not work, at present i get pointer to structure error message
*listItem[index].dataList = data;//this way gives me a lvalue error message
//any help will be greatly appreciated
}
i removed some of the code to keep the post size down
listitem is a struct vector *
listitem[index] is a struct vector
listitem[index].dataList is a char *
* listitem[index].datalist is a char
listitem[index] -> datalist doesn't mean anything, since listitem[index] isn't a struct *
data is a char *
* listitem[index].datalist = data
tries to put a char * value into a char. Try using a string copy command instead.
Callou collei we'll code the way
Of prime numbers and pings!
If you're using indexes to access the elements then you don't need to use pointer notation, and if you're coping strings you'll need to use strcpy() -
strcpy(listItem[index].dataList,data);
zen
hehe, thanx guys, thats got me back on course again
that one had me stumped for a couple of days, i thought i had tried everything aswell
thanx again
