Thread: Sorting numbers in a file

The title is misleading in that the numbers in the file are displayed in a column.

Example:

3
5
10
4
8
1
2
etc...

The resulting file also has to be in that formatting, so:

1
2
3
4
5
6

The problem I am having right now is getting the numbers read from the file and into an array. The problem is that I have it reading character by character so if it is a two digit number, say 10, it will put 1 into one element and 0 into another one. That is one problem I know about. The other major one is how I can print the array, once it is sorted, back into another file with that above formatting. Here is what I have working right now.....

Code:

void quicksort(int *array, int size)     //sorting function for the array
{
   int a,b,temp;

   for(a=0;a<(size-1);a++){
     for(b=a=1;b<size;b++){
       if(array[a] > array [b]){
         temp=array[b];
         array[b] = array[a];
         array[a] = temp;
       }
     }
   }
}

int main(int argc, char *argv[])
{

FILE *quick, *fp;
char c;
int n;
int array[101];

    fp=fopen(argv[1], "r");
    quick=fopen("sorted", "w");

    while((c=fgetc(fp)) != EOF){   //gets the numbers, put them into an array
      for(n=0; n <101; n++){
        if(c != '\n'){
          array[n] = c;
        }
      }
    }

    quicksort(array, 101);        //sort the numbers

    while(array != NULL){      //Puts the numbers back into a new file
      for(n=0; n <101; n++){
          fputc(array[n],quick);
      }
    }


fclose(quick);

      system("PAUSE");
      return 0;
}