Thread: Avg. Number Proggie

Originally Posted by WaltP

What variable are you 'scanf'ing into?
What variable is holding your total?
Is there a conflict?

expalain that a bit more to me on where the problem lay walt. I coded it on the fly so i was expecting it to work. Here is a corrected version,Define MAX to be whatever u want

Code:

#include <stdio.h>
#include <stdlib.h>
#define MAX 4



int main(void){

   int count;
   float num, avg;

   for(count=1; count<=MAX; count++){
       printf("Enter in num %d\n", count);
       scanf("%f", &num);
       num+=num;
       avg = num/MAX;
   }
  printf("The average is %.2f\n", avg);
  system("pause");
  return 0;
}

Originally Posted by caroundw5h

expalain that a bit more to me on where the problem lay walt. I coded it on the fly so i was expecting it to work.

You are expecting "on-the-fly" code to work? If you spend time on it do you expect it to not work? The problem with "on-the-fly" code is usually it does not work

Originally Posted by caroundw5h

Code:

for(count=1; count<=MAX; count++){
    printf("Enter in num %d\n", count);
    scanf("%f", &num);
    num+=num;
    avg = num/MAX;
}

Walk thru this code with pencil & paper, keeping track of all the variables as they change. You will see exactly where the problem is.

They mean it doesn't work:

Code:

for( x = 1; x <=4; x++ )
{
    /* first time through loop */
    scanf into number /* say they input 5 */
    number = number + number /* number now is 10 */

    /* second time through loop */
    scanf into number /* say the input is 6 */
    number = number + number /* number is now 12 */

    /* third time through loop */
    scanf into number /* say the input is 7 */
    number = number + number /* number is now 14 */
}

See the problem yet? Had you actually walked through the code like they suggested, you'd see the problem.

Quzah.