String manipulation

[fergy]

Hi,
I have recently started programming in C and would like so guidance.
What I would like is I have read a string infor eg.
' the brown cow jumped over the fox'
the string will vary what I would like to do is read the string till I come across a space and change the space to an underscore if at all possible so the string would read
' the_brown_cow_jumped_over_the_fox'
and then back again to the spaces.
Thank you very much
fergy

[anonytmouse]

Welcome to the boards!

while (char at pos does not equal '\0') /* Loop till end of string */
    if (char at pos equals ' ') make char at pos equal '_';
    pos = pos plus one; /* Move to next character */
loop;

You'll need to convert the abstract idea into real code.
If you need further help, consider posting what you have tried.

[fergy]

while (char at pos does not equal '\0') /* Loop till end of string */
if (char at pos equals ' ') make char at pos equal '_';
pos = pos plus one; /* Move to next character */
loop;


while (people[t].address2!= '\0') Loop till end of string */
{
if( *people[t].address2 == ' ') /*replace a space in the string with an _*/
*people[t].address2 == '_';
pos = pos++; /* Move to next character */
} /*end while loop*/

where pos is equal to the & *people[t].address2
not sure if that is rightas the program hangs on the last item before this loop.

Thank you for all your help
fergy

[tzuchan]

I'am assuming you have an array of a structure that looks something like this:

struct human
{

char address1[20];
char address2[20];
.
.
.
};

int main(void)
{

struct human people[5]; //creates an array of 5 humans
int i = 0, t = 0;
while (people[t].address2[i]!= '\0') Loop till end of string */
{

if( *people[t].address2[i] == ' ') /*replace a space in the string with an _*/
*people[t].address2[i] == '_';
i++; /* Move to next character */
} /*end while loop*/
}

This isn't anywhere near a complete code. The thing is, strings are actually arrays of characters, and as such, when doing a comparison character by character, treat it like how you would compare an array element by element.

[Sebastiani]

You could simplify the syntax a bit by doing:

char * t = people[t].address2;

- or -

char * t = &people[t].address2[0];

...then...

 while(*t != 0)
{
     if(*t == ' ')
   {
     *t = '_';
   }
 
 t++;
}

- or -

int a = 0;

 while(t[a] != 0)
{
     if(t[a] == ' ')
   {
     t[a] = '_';
   }
 
 a++;
}