Thread: using a driver function to test my code??

All I do when I start Visual C++ is go to New, then Files, then C++ source file and I type and compile the code. I don't even use the command line. Is there something I should be doing that would help me? Like adjusting the settings? When I went to project and settings, the settings are grayed out and I cannot select it. Probably because I am going into the project. I have only used Microsoft Visual C++ 6.0 to create and compile Visual Basic programs. I have used this compiler through Visual Basic and Advanced Visual Basic and so far, I like it. So why spend money to buy another compiler when this one works fine? I first installed the Borland Compiler, but I really didn’t care for it and I had trouble setting it up to work properly on my computer. If there are settings that I should adjust or change that will help me, as a student, learn more, I would like to know. Thanks......

When you are working on a new project, start off by creating a new project. If you don't then it'll automatically make one when you try to compile a file. Then once you're done that the Project Settings should no longer be greyed out.

Go to C/C++->General
and set warning level to level 4.
Also in category Customize, check the box marked 'disable language extentions'

There are better compilers which are free, but the development environment in Visual Studio is excellent. Stick with what you've got.

Awesome...thanks for the tip

I still dont understand what this means:

If ch is not a digit between '0' and '9', then the function returns a value of 0. Otherwise......................followed by a newline character and has a return value of 1. The program is complete, except for this part.

Sorry for asking again, but I am alittle consfused. Thanks again. You all have been a great help. tommy

Originally posted by tommy69
I still dont understand what this means:

If ch is not a digit between '0' and '9', then the function returns a value of 0. Otherwise......................followed by a newline character and has a return value of 1. The program is complete, except for this part.

Sorry for asking again, but I am alittle consfused. Thanks again. You all have been a great help. tommy

Post your code.

Your writeNumber function should return 0 if the user typed a number, or 1 if they didn't.

Originally posted by WaltP
Is there some important information removed from your post where "......................" is? That sentence doesn't read correctly and I fear there may be important information missing.

First post:

I need to create a function called writeNumber() using the switch statement. The input argument is ch of type char. Now, if ch is not a digit between '0' and '9', then the function returns the value 0 (I can use the isidigit() function). Oherwise, the function writes to the screen the correct English word of the digit charatcer followed by a newline charatcer and has a return value of 1. Once I write the function, I have to use the following driver to test my function:

Thanks Major_blagger...I didnt get to the post quick enough as I would of explained the............. Here is my code. If the user types in a letter, the driver function prints "That wasn't a number key!" Once the word is printed, say "One", I have the \n, but is it returning a value of 1? Why is it or why is it not? The bottom of the code has else x=0, meaning that if the user types anything but a digit, then x=0. Hope this is correct. Thanks for your help.

Code:

#include <stdio.h>
#include <ctype.h>
#include <conio.h>

int writeNumber(int);

void main()							/*DRIVER FUNCTION*/
{
	char ch;
	int num;

	printf("Hit any number key>>");
	ch=(char) getch();
	printf("\nYou entered %c>>",ch);

	num=writeNumber(ch);
	if (num==0)
		printf("\nThat wasn't a number key!\n");
}

int writeNumber(int x)
{

 if (isdigit (x)) /* If input equals a number,perform the switch statement */

	switch (x)
	{
	case '0':
		printf("Zero\n");
		break;
	case '1':
		printf("One\n");
		break;
	case '2':
		printf("Two\n");
		break;
	case '3':
		printf("Three\n");
		break;
	case '4':
		printf("Four\n");
		break;
	case '5':
		printf("Five\n");
		break;
	case '6':
		printf("Six\n");
		break;
	case '7':
		printf("Seven\n");
		break;
	case '8':
		printf("Eight\n");
		break;
	case '9':
		printf("Nine\n");
		break;
	}
	else   x=0;	/* If user types anything but a number, x = 0 */
		
	 			
	return (x);	 /*x is returned to the function */
}