time

[cigcode]

how would i access tm_year in this program

#include <time.h>
#include <stdio.h>

int main( )
{
    time_t today;
    char *now, buff[20];
    
    struct tm* gettime;
    
    time( &today );
    
    gettime = localtime( &today );
    now = asctime(( const struct tm* ) gettime );
    
    strftime(buff, 80, now, gettime);
    
    printf( "%s %d", buff, gettime );
  
    getch( );
}

[c99]

#include <time.h>
#include <stdio.h>

int main(void)
{
	struct tm* tmp;

	time_t t = time(NULL);

	tmp = localtime(&t);

	printf("%d", tmp->tm_year);

	return 0;
}

In your example code gettime->tm_year holds years since 1900.

[cigcode]

ahh i c what you did.. you also added a NULL in the time fuction.. hmm so NULL == current time correct.. i should of thought of this before its like mysql with a colum of datetime.. now i get it.. 10x

[Prelude]

>hmm so NULL == current time correct..
To a certain extent. The time function returns the current calendar time or (time_t)-1 if the time is not available. Time also takes a pointer to time_t as an argument. If that pointer is not NULL then the current calendar time is assigned to it as well. So tests that use the return value directly:

time_t now;

if ( ( now = time ( NULL ) ) != (time_t)-1 ) {
  /* Work with now */
}

Can be written so that they're easier to read:

time_t now;

if ( time ( &now ) != (time_t)-1 ) {
  /* Work with now */
}

now = time ( NULL );

and

time ( &now );

do the same thing, they just get there in a different way.

[cigcode]

ah ok i get.. but what i dont get is why this is giving me the value of 104 instead of 04 or 2004

struct tm* gettime;
    
    time_t t = time( NULL );
    char *now, buff[20];
    
    gettime = localtime( &t );
    
    printf( "Year: %d\n\n", gettime->tm_year );

should'nt it just give me 2004 or 04

[c99]

1900 + 104 == 2004.

The tm_year member of struct tm yields years since 1900.

Take a peek. http://www-ccs.ucsd.edu/c/time.html#tm

[cigcode]

ic thank you again.