Thread: asctime()

  1. #1
    Registered User Draco's Avatar
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    Apr 2002
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    463

    asctime()

    I'm trying to use the function asctime() and save the function output to a string, but I can't figure out how to do it. What I've posted is the only way I can get it to compile without errors, but it's obviously wrong. Am I missing something obvious?
    Code:
    main()
    {
       time_t lt;
       struct tm t, *tmptr;
       
       lt=time(NULL);
       tmptr=localtime( & lt );
       char strings[26];
       const char *chptr=strings;
       chptr=asctime(tmptr);
       printf("%s\n%s",asctime(tmptr),strings);
       return 0;
    }

  2. #2
    and the hat of int overfl Salem's Avatar
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    You mean

    strcpy(strings,asctime(tmptr));

    You're writing C++ with those embedded declarations you know.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  3. #3
    Registered User Draco's Avatar
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    Thanks Salem, that was a little obvious I guess I don't work with the standard functions enough. And no, I wasn't sure if it was C++ or not, but I have seen it in my C++ book

  4. #4
    .
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    Code:
    #include <time.h>
    
    int main(int argc, char *argv[])                                     
    {                                          
       time_t lt;                              
       struct tm t, *tmptr;                    
       char tmp[26]={'\0'};                                         
       lt=time(NULL);                          
       tmptr=localtime( & lt );                
       strcpy(tmp,asctime(tmptr));                   
       printf("%s\n",asctime(tmptr));
       printf("%s\n",tmp);
       return 0;                               
    }
    asctime() returns a static char *, which will change with subsequent calls to time functions; this makes a local copy.

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