I'm officially stuck

[caroundw5h]

Why is this code only assigning the ascii value to the arrray. I want it to print out the letters ex:

array element 0= a
array element 1 = b

what Am i doing wrong.?

Here are the two scripts i coded. I thought the second would work, but it didn't. I was so excited to wake up this morning cause i thought i had solved it but .....

 code 1

/* alpaarray.c intializes a 26 element array to the ltrs of the alphabet and
* displays it */

#include<stdio.h>
#define SIZE 26

int main(void)

{

    int ndx;
    char alphabet[SIZE];
    char ltr;

    /* outer loop to count to 26 */

    for (ndx = 0; ndx < SIZE; ndx++)
    {
        for (ltr = 'a'; ltr <= ('a' + ndx); ltr ++)
            alphabet[ndx] = ltr;/* assigning only ascii value */
        printf("Alphabet element number %3d is %3d\n", ndx, alphabet[ndx]);

    }




     getchar();
     return (0);

}

/* ltrarray2.c intialises a character array to ltr of the alphabet */

#include <stdio.h>
#define SIZE 26

int main(void)

{

    int row;
    char alpha[SIZE], ltr;

    /* set up rows */

    for (row = 0, ltr = ('a' + row); row < SIZE; row++,ltr++)
        alpha[row] = ltr;

    /* print elements of row */
    for (row = 0; row < SIZE; row++)
        printf("Element %3d  of Alpha array is %3d\n", row, alpha[row]);



    getchar();
    return (0);


}

[LittleJohn]

You have to use the conversion specifier %c to print the character the integer stored in memory represents. for example:

char variable = 'a';

printf("%d = %c", variable, variable);

would print the output:

97 = a

edit
Just some more thought on this.... your PC's memory can only hold numerical data. So if you're storing a string in the memory, you're really just storing the ASCII integers assigned to whatever letters you are using.

[caroundw5h]

Just some more thought on this.... your PC's memory can only hold numerical data. So if you're storing a string in the memory, you're really just storing the ASCII integers assigned to whatever letters you are using.

Thank you , I understand that a char is really still an integer, which is why my code outputted the ascii value. However why the hell didn't it it print out the character value if i had already assigned the chara - never mind. I get it now. Seems I still have to implicityl declare it as a character.

*smacks forhead* god its so simple and so fu***ing annoying. I assumed that once i had assigned the characte value to it.

 for (ltr = 'a'; ltr <= ('a' + ndx); ltr ++)
            alphabet[ndx] = ltr;

Then it was saved as a character. But I forgot that even when printing it out, I can choose how it will be outputted. Thank you, very much.

The friggin annoyances of C i keep forgetting them.